boost中的数字范围迭代器?

问题描述

我知道 boost 中的范围迭代器，对于 this reference，似乎应该有一种简单的方法来做我想做的事，但这对我来说并不明显.

I'm aware of the range iterators in boost, and as for this reference, it seems there should be an easy way of doing what I want, but it's not obvious to me.

假设我想表示一个数字范围，0 到 100(包括或不包括)，比如 range(0,100).我想做类似的事情:

Say I want to represent a numerical range, 0 to 100 (inclusive or not), say range(0,100). I would like to do something like:

for_each(range<int>(0,100).begin(), range<int>(0,100).end(), do_something);

do_something 是一个仿函数.这个迭代器不应该有一个底层向量或类似的东西的开销，而只是提供一个整数序列.这可能与boost中的范围实现有关吗?使用普通的标准 STL 迭代器完全可以吗?

where do_something is a functor. This iterators shouldn't have the overhead of having an underneath vector or something like this, but to just offer a sequence of integers. Is this possible with the range implementation in boost? Possible at all with normal, standard STL iterators?

推荐答案

boost::counting_iterator

#include <boost/iterator/counting_iterator.hpp>

std::for_each( boost::counting_iterator<int>(0),
               boost::counting_iterator<int>(100),
               do_something );

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