Is there XNOR (Logical biconditional) operator in C#?(C# 中是否有 XNOR(逻辑双条件)运算符?)

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问题描述

我是 C# 新手，找不到 XNOR 运算符来提供这个真值表:

<上一页>a b a XNOR b----------------T T T对了F T FF F T

是否有专门的运营商来做这件事?或者我需要使用 !(A^B)?

解决方案

XNOR 只是布尔值上的相等；使用 A == B.

这很容易被忽略，因为相等性通常不应用于布尔值.并且有些语言不一定有效.例如，在 C 中，任何非零标量值都被视为真，因此两个真"值可能不相等.但是问题被标记为 c#，它有，容我们说，表现良好的布尔值.

另请注意，这并不适用于按位运算，您需要 0x1234 XNOR 0x5678 == 0xFFFFBBB3(假设为 32 位).为此，您需要从其他操作构建，例如 ~(A^B).(注意:~，而不是 !.)

I'm new to C# and could not find XNOR operator to provide this truth table:

a  b    a XNOR b
----------------
T  T       T
T  F       F
F  T       F
F  F       T

Is there a specific operator for this? Or I need to use !(A^B)?

解决方案

XNOR is simply equality on booleans; use A == B.

This is an easy thing to miss, since equality isn't commonly applied to booleans. And there are languages where it won't necessarily work. For example, in C, any non-zero scalar value is treated as true, so two "true" values can be unequal. But the question was tagged c#, which has, shall we say, well-behaved booleans.

Note also that this doesn't generalize to bitwise operations, where you want 0x1234 XNOR 0x5678 == 0xFFFFBBB3 (assuming 32 bits). For that, you need to build up from other operations, like ~(A^B). (Note: ~, not !.)

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