Parsing timestamp as LocalDateTime(将时间戳解析为 LocalDateTime)
问题描述
我想将 yyyy-MM-dd'T'HH:mm:ss
形式的时间戳解析为 LocalDateTime
.这样做时,如果它们是 00
,它会去除秒数.
I want to parse a timestamp in the form of yyyy-MM-dd'T'HH:mm:ss
as LocalDateTime
. When doing so, it strips the seconds if they are 00
.
如此处所述,我需要使用自定义格式化程序
As described here, I need to use a custom formatter
这个可行,但它返回一个 String
:
This one works, but it returns a String
:
当我将字符串解析为 LocalDateTime
时,它会再次剥离 00
:
When I parse the string to LocalDateTime
it strips the 00
again:
那么如何将日期解析为 LocalDateTime
,而不是 String
,并在末尾保留 00
?
So how can I parse a date as LocalDateTime
, instead of String
, and keep the 00
at the end?
推荐答案
你应该期待两者之间的输出差异
You should expect a difference in output between
还有
System.out.println(dateLDT);
打印 dateLDT.toString()
的值,预计不会产生与您的模式相同的输出.
System.out.println(dateLDT);
prints the value of dateLDT.toString()
, which is not expected to produce the same output as your pattern.
当您查看 LocalDateTime.toString()
时,您会看到它将时间部分委托给 LocalTime.toString()
,它有条件地打印秒数:
When you look at LocalDateTime.toString()
, you'll see that it delegates the time part to LocalTime.toString()
, which prints seconds conditionally:
如果它的值为0
,它只是省略秒字段.
It simply omits the seconds field if its value is 0
.
在这种情况下,如果您必须确定输出/输入格式,您需要始终使用 DateTimeFormatter
来格式化您的日期.
What you need to do in this case is always use a DateTimeFormatter
to format your date if you have to be certain about the output/input format.
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