[UITapGestureRecognizer tag]:发送到实例的无法识别的选择器

问题描述

我正在安排一系列 imageview，并为其分配一个 TapView 识别器

I am having a series of imageview arranged, and assigning a TapView recognizer to it

UITapGestureRecognizer *tapRecognizer = [[UITapGestureRecognizer alloc]
                                         initWithTarget:self action:@selector(action:)];
[tapRecognizer setNumberOfTouchesRequired:1];
[tapRecognizer setDelegate:self];
imageView.userInteractionEnabled = YES;
[imageView addGestureRecognizer:tapRecognizer];

我将选择器定义为:

-(void) action:(id)sender
  {
    NSLog(@"TESTING TAP");
    NSLog (@"%d",[sender tag]);
  }

这正在崩溃，我收到错误消息:-

This is getting Crashed and i am getting Error message as:-

[UITapGestureRecognizer tag]:无法识别的选择器发送到实例 0x145d0210

推荐答案

你可以用这个..

UITapGestureRecognizer *tapRecognizer = [[UITapGestureRecognizer alloc]
                                         initWithTarget:self action:@selector(action:)];
[tapRecognizer setNumberOfTouchesRequired:1];
[tapRecognizer setDelegate:self];
imageView.userInteractionEnabled = YES;
imageView.tag = 1111;
[imageView addGestureRecognizer:tapRecognizer];

在行动中试试这个..

-(void) action:(id)sender
  {
    NSLog(@"TESTING TAP");
    UITapGestureRecognizer *tapRecognizer = (UITapGestureRecognizer *)sender;
    NSLog (@"%d",[tapRecognizer.view tag]);
  }

说明:

UITapGestureRecognizer 没有像 tag 这样的属性.但它有属性 view，从这个属性你可以访问 UITapGestureRecognizer 所附加的视图.

UITapGestureRecognizer has not property like tag. but it has property view, from this property you can access the view with which UITapGestureRecognizer was attached.

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