How to Exponential Backoff retry on kotlin coroutines(如何在Kotlin协程上进行指数退避重试)
问题描述
我正在使用Kotlin协程进行网络请求,使用扩展方法调用改造中的类,如下所示
public suspend fun <T : Any> Call<T>.await(): T {
return suspendCancellableCoroutine { continuation ->
enqueue(object : Callback<T> {
override fun onResponse(call: Call<T>?, response: Response<T?>) {
if (response.isSuccessful) {
val body = response.body()
if (body == null) {
continuation.resumeWithException(
NullPointerException("Response body is null")
)
} else {
continuation.resume(body)
}
} else {
continuation.resumeWithException(HttpException(response))
}
}
override fun onFailure(call: Call<T>, t: Throwable) {
// Don't bother with resuming the continuation if it is already cancelled.
if (continuation.isCancelled) return
continuation.resumeWithException(t)
}
})
registerOnCompletion(continuation)
}
}
那么从调用端我就是这样使用上面的方法
private fun getArticles() = launch(UI) {
loading.value = true
try {
val networkResult = api.getArticle().await()
articles.value = networkResult
}catch (e: Throwable){
e.printStackTrace()
message.value = e.message
}finally {
loading.value = false
}
}
我想在某些情况下指数重试此API调用,即(IOException)如何实现??
推荐答案
我建议为您的重试逻辑编写帮助器higher-order function。您可以使用以下实现作为起点:
suspend fun <T> retryIO(
times: Int = Int.MAX_VALUE,
initialDelay: Long = 100, // 0.1 second
maxDelay: Long = 1000, // 1 second
factor: Double = 2.0,
block: suspend () -> T): T
{
var currentDelay = initialDelay
repeat(times - 1) {
try {
return block()
} catch (e: IOException) {
// you can log an error here and/or make a more finer-grained
// analysis of the cause to see if retry is needed
}
delay(currentDelay)
currentDelay = (currentDelay * factor).toLong().coerceAtMost(maxDelay)
}
return block() // last attempt
}
使用此函数非常简单:
val networkResult = retryIO { api.getArticle().await() }
您可以根据具体情况更改重试参数,例如:
val networkResult = retryIO(times = 3) { api.doSomething().await() }
您还可以完全更改retryIO
的实现,以适应您的应用程序的需要。例如,您可以硬编码所有重试参数、取消重试次数限制、更改默认值等。
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