Trying to get property of non-object error in Yii(试图在 Yii 中获取非对象错误的属性)

本文介绍了试图在 Yii 中获取非对象错误的属性的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

案例 1:我得到一个 CActiveRecords 数组并尝试循环遍历它，如下所示:

Case 1: I get an array of CActiveRecords and try to loop over it as shown below:

foreach ($pendingTasks as $task)
    {
        if($task->task->employee_id=="1")
        {
            //some logic here
        }
    }

我得到试图获取非对象的属性"

I get "Trying to get property of non-object "

案例 2:如果我尝试:

Case 2: If I try:

$pendingTasks = TaskLog::model()->findByPk("1");
    if($pendingTasks->task->employee_id=="1")
    {
        //some logic here   
    }

这有效.为什么会这样?我在这里做错了什么吗?

This works. Why is this so? Am I doing any thing wrong here?

推荐答案

因为 $pendingTasks 中的 tasks 不能有关系.您可以通过简单地添加一个 isset() 来检查:

Because of the tasks in $pendingTasks must not have a relation. You can check by simply adding an isset() like so:

foreach ($pendingTasks as $task) {
    if(isset($task->task) && $task->task->employee_id=="1") {
        //some logic here
    } else {
        echo "{$task->id} doesn't have a task relation";
    }
}

假设 $pendingTasks 也是 TaskLog 的实例.

Assuming $pendingTasks are instances of TaskLog also.

这篇关于试图在 Yii 中获取非对象错误的属性的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！