如何计算数组中连续的重复值?

问题描述

我有一个这样的数组:

$arr = array(1, 1, 1, 2, 2, 3, 3, 1, 1, 2, 2, 3);

我找到了函数 array_count_values()，但它会将所有相同的值分组并计算出现次数，而不考虑连续序列中的中断.

I found the function array_count_values(), but it will group all of the same values and count the occurrences without respecting breaks in the consecutive sequences.

$result[1] = 5
$result[2] = 4
$result[3] = 3

如何对每组连续值进行分组并计算每个序列的长度?请注意，数字 1、2 和 3 有两组序列.

How can I group each set of consecutive values and count the length of each sequence? Notice there are two sets of sequences for the numbers 1, 2, and 3.

我期望生成的数据需要类似于:

The data that I expect to generate needs to resemble this:

[1] = 3;
[2] = 2;
[3] = 2;
[1] = 2;
[2] = 2;
[3] = 1;

推荐答案

只需手动即可:

$arr = array(1,1,1,2,2,3,3,1,1,2,2,3);

$result = array();
$prev_value = array('value' => null, 'amount' => null);

foreach ($arr as $val) {
    if ($prev_value['value'] != $val) {
        unset($prev_value);
        $prev_value = array('value' => $val, 'amount' => 0);
        $result[] =& $prev_value;
    }

    $prev_value['amount']++;
}

var_dump($result);

这篇关于如何计算数组中连续的重复值?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！