从 Dom 元素获取 CSS 路径

问题描述

我得到了这个函数来获取一个 cssPath :

I got this function to get a cssPath :

var cssPath = function (el) {
  var path = [];

  while (
    (el.nodeName.toLowerCase() != 'html') && 
    (el = el.parentNode) &&
    path.unshift(el.nodeName.toLowerCase() + 
      (el.id ? '#' + el.id : '') + 
      (el.className ? '.' + el.className.replace(/s+/g, ".") : ''))
  );
  return path.join(" > ");
}
console.log(cssPath(document.getElementsByTagName('a')[123]));

但我得到了这样的东西:

But i got something like this :

html > body > div#div-id > div.site > div.clearfix > ul.choices > li

但完全正确，它应该是这样的:

But to be totally right, it should look like this :

html > body > div#div-id > div.site:nth-child(1) > div.clearfix > ul.choices > li:nth-child(5)

有人有什么想法可以简单地在 javascript 中实现它吗?

Did someone have any idea to implement it simply in javascript ?

推荐答案

要始终获得正确的元素，您需要使用 :nth-child() 或 :nth-of-type() 用于不唯一标识元素的选择器.所以试试这个:

To always get the right element, you will need to use :nth-child() or :nth-of-type() for selectors that do not uniquely identify an element. So try this:

var cssPath = function(el) {
    if (!(el instanceof Element)) return;
    var path = [];
    while (el.nodeType === Node.ELEMENT_NODE) {
        var selector = el.nodeName.toLowerCase();
        if (el.id) {
            selector += '#' + el.id;
        } else {
            var sib = el, nth = 1;
            while (sib.nodeType === Node.ELEMENT_NODE && (sib = sib.previousSibling) && nth++);
            selector += ":nth-child("+nth+")";
        }
        path.unshift(selector);
        el = el.parentNode;
    }
    return path.join(" > ");
}

您可以添加一个例程来检查其相应上下文中的唯一元素(如 TITLE、BASE、CAPTION 等).

You could add a routine to check for unique elements in their corresponding context (like TITLE, BASE, CAPTION, etc.).

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