将文件从 Javascript 上传到 PHP

素材狗 2022-01-01 23:24:24 文章分类：前端问题点击数：次

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Pass file from Javascript upload to PHP(将文件从 Javascript 上传到 PHP)

本文介绍了将文件从 Javascript 上传到 PHP的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我正在编写一个脚本，让用户上传文件并查看上传状态，然后将文件保存在服务器上.

问题是我无法使用 php api.所以我想用javascript上传文件，在那里我可以轻松获得上传状态，但我想将文件传递给php并保存.

这可能吗?

这是要上传的 javascript 代码.

<!DOCTYPE html><html><头><title>使用 XMLHttpRequest 上传文件</title><脚本类型="文本/javascript">功能文件选择(){var file = document.getElementById('fileToUpload').files[0];如果(文件){var 文件大小 = 0;如果(文件大小> 1024 * 1024)fileSize = (Math.round(file.size * 100/(1024 * 1024))/100).toString() + 'MB';别的fileSize = (Math.round(file.size * 100/1024)/100).toString() + 'KB';document.getElementById('fileName').innerHTML = '名称:' + file.name;document.getElementById('fileSize').innerHTML = 'Size: ' + fileSize;document.getElementById('fileType').innerHTML = '类型:' + file.type;}}函数上传文件(){var fd = new FormData();fd.append("fileToUpload", document.getElementById('fileToUpload').files[0]);var xhr = new XMLHttpRequest();xhr.upload.addEventListener("进度", uploadProgress, false);xhr.addEventListener("加载", uploadComplete, false);xhr.addEventListener("错误", uploadFailed, false);xhr.addEventListener("abort", uploadCanceled, false);xhr.open("POST", "UploadHandler.ashx");xhr.send(fd);}函数上传进度(evt){如果(evt.lengthComputable){var percentComplete = Math.round(evt.loaded * 100/evt.total);document.getElementById('progressNumber').innerHTML = percentComplete.toString() + '%';document.getElementById('prog').value = percentComplete;}别的 {document.getElementById('progressNumber').innerHTML = '无法计算';}}函数上传完成(evt){/* 当服务器发回响应时引发此事件 */警报(evt.target.responseText)；}函数上传失败(evt){alert("上传文件时出错.");}函数上传取消(evt){alert("上传已被用户取消或浏览器断开连接.");}</脚本></头><身体><form id="form1"><label for="fileToUpload">选择要上传的文件</label><input type="button" onclick="uploadFile()" value="Upload"/></div><div id="progressNumber"></div><progress id="prog" value="0" max="100.0"></progress></表格></身体></html>

解决方案

我对此有一个Gist.它使用 xhr.send(FormData) 并显示最少的代码用 PHP 处理文件.

I'm working on a script to let the user upload a file and sees a upload status and the file is then saved on the server.

The problem is that I cannot use the php api. So I was thinking to upload the file with javascript where I can easly get the upload status but then I want to pass the file to php and save it.

Is this possible?

This is the javascript code to upload.

<!DOCTYPE html>
<html>
<head >
<title>Upload Files using XMLHttpRequest</title>

<script type="text/javascript">
    function fileSelected() {
        var file = document.getElementById('fileToUpload').files[0];
        if (file) {
            var fileSize = 0;
            if (file.size > 1024 * 1024)
                fileSize = (Math.round(file.size * 100 / (1024 * 1024)) / 100).toString() + 'MB';
            else
                fileSize = (Math.round(file.size * 100 / 1024) / 100).toString() + 'KB';

            document.getElementById('fileName').innerHTML = 'Name: ' + file.name;
            document.getElementById('fileSize').innerHTML = 'Size: ' + fileSize;
            document.getElementById('fileType').innerHTML = 'Type: ' + file.type;
        }
    }

    function uploadFile() {
        var fd = new FormData();
        fd.append("fileToUpload", document.getElementById('fileToUpload').files[0]);
        var xhr = new XMLHttpRequest();
        xhr.upload.addEventListener("progress", uploadProgress, false);
        xhr.addEventListener("load", uploadComplete, false);
        xhr.addEventListener("error", uploadFailed, false);
        xhr.addEventListener("abort", uploadCanceled, false);
        xhr.open("POST", "UploadHandler.ashx");
        xhr.send(fd);
    }

    function uploadProgress(evt) {
        if (evt.lengthComputable) {
            var percentComplete = Math.round(evt.loaded * 100 / evt.total);
            document.getElementById('progressNumber').innerHTML = percentComplete.toString() + '%';
            document.getElementById('prog').value = percentComplete;
        }
        else {
            document.getElementById('progressNumber').innerHTML = 'unable to compute';
        }
    }

    function uploadComplete(evt) {
        /* This event is raised when the server send back a response */
        alert(evt.target.responseText);
    }

    function uploadFailed(evt) {
        alert("There was an error attempting to upload the file.");
    }

    function uploadCanceled(evt) {
        alert("The upload has been canceled by the user or the browser dropped the connection.");
    }
</script>

</head>
<body>
    <form id="form1">
    <div>
        <label for="fileToUpload">
            Select a File to Upload</label>
        <input type="file" name="fileToUpload[]" id="fileToUpload" onchange="fileSelected();" />
    </div>
    <div id="fileName">
    </div>
    <div id="fileSize">
    </div>
    <div id="fileType">
    </div>
    <div>
        <input type="button" onclick="uploadFile()" value="Upload" />
    </div>
    <div id="progressNumber">
    </div>
    <progress id="prog" value="0" max="100.0"></progress>
    </form>
</body>
</html>

解决方案

I have a Gist on this. It uses xhr.send(FormData) and shows minimal code to handle the file in PHP.

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